(k^2-9k+3)/(k-1)

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Solution for (k^2-9k+3)/(k-1) equation:


D( k )

k-1 = 0

k-1 = 0

k-1 = 0

k-1 = 0 // + 1

k = 1

k in (-oo:1) U (1:+oo)

(k^2-(9*k)+3)/(k-1) = 0

(k^2-9*k+3)/(k-1) = 0

k^2-9*k+3 = 0

k^2-9*k+3 = 0

DELTA = (-9)^2-(1*3*4)

DELTA = 69

DELTA > 0

k = (69^(1/2)+9)/(1*2) or k = (9-69^(1/2))/(1*2)

k = (69^(1/2)+9)/2 or k = (9-69^(1/2))/2

(k-((9-69^(1/2))/2))*(k-((69^(1/2)+9)/2)) = 0

((k-((9-69^(1/2))/2))*(k-((69^(1/2)+9)/2)))/(k-1) = 0

( k-((69^(1/2)+9)/2) )

k-((69^(1/2)+9)/2) = 0 // + (69^(1/2)+9)/2

k = (69^(1/2)+9)/2

( k-((9-69^(1/2))/2) )

k-((9-69^(1/2))/2) = 0 // + (9-69^(1/2))/2

k = (9-69^(1/2))/2

k in { (69^(1/2)+9)/2, (9-69^(1/2))/2 }

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